Is the following code legal?
using System;
namespace Demo
{
class Program
{
public static void Main()
{
}
public void Sum(int FirstNumber, int SecondNumber)
{
int Result = FirstNumber + SecondNumber;
}
public int Sum(int FirstNumber, int SecondNumber)
{
int Result = FirstNumber + SecondNumber;
}
}
}
No, The above code does not compile. You cannot overload a method based on the return type. To overload a method in C# either the number or type of parameters should be different. In general the return type of a method is not part of the signature of the method for the purposes of method overloading. However, it is part of the signature of the method when determining the compatibility between a delegate and the method that it points to.
What is the difference between method parameters and method arguments. Give an example?
In the example below FirstNumber and SecondNumber are method parameters where as FN and LN are method arguments. The method definition specifies the names and types of any parameters that are required. When calling code calls the method, it provides concrete values called arguments for each parameter. The arguments must be compatible with the parameter type but the argument name (if any) used in the calling code does not have to be the same as the parameter named defined in the method.
using System;
namespace Demo
{
class Program
{
public static void Main()
{
int FN = 10;
int SN = 20;
//FN and LN are method arguments
int Total = Sum(FN, SN);
Console.WriteLine(Total);
}
//FirstNumber and SecondNumber are method parameters
public static int Sum(int FirstNumber, int SecondNumber)
{
int Result = FirstNumber + SecondNumber;
return Result;
}
}
}
Explain the difference between passing parameters by value and passing parameters by reference with an example?
We can pass parameters to a method by value or by reference. By default all value types are passed by value where as all reference types are passed by reference. By default, when a value type is passed to a method, a copy is passed instead of the object itself. Therefore, changes to the argument have no effect on the original copy in the calling method.An example is shown below.
using System;
namespace Demo
{
class Program
{
public static void Main()
{
int I = 10;
int K = Function(I);
Console.WriteLine("I = " + I);
Console.WriteLine("K = " + K);
}
public static int Function(int Number)
{
int ChangedValue = Number + 1;
return ChangedValue;
}
}
}
By default, reference types are passed by reference. When an object of a reference type is passed to a method, the reference points to the original object, not a copy of the object. Changes made through this reference will therefore be reflected in the calling method. Reference types are created by using the class keyword as shown in the example below.
using System;
namespace Demo
{
class Program
{
public static void Main()
{
ReferenceTypeExample Object = new ReferenceTypeExample();
Object.Number = 20;
Console.WriteLine("Original Object Value = " + Object.Number);
Function(Object);
Console.WriteLine("Object Value after passed to the method= " + Object.Number);
}
public static void Function(ReferenceTypeExample ReferenceTypeObject)
{
ReferenceTypeObject.Number = ReferenceTypeObject.Number + 5;
}
}
class ReferenceTypeExample
{
public int Number;
}
}
Can you pass value types by reference to a method?
Yes, we can pass value types by by reference to a method. An example is shown below.
using System;
namespace Demo
{
class Program
{
public static void Main()
{
int I = 10;
Console.WriteLine("Value of I before passing to the method = " + I);
Function(ref I);
Console.WriteLine("Value of I after passing to the method by reference= " + I);
}
public static void Function(ref int Number)
{
Number = Number + 5;
}
}
}
If a method's return type is void, can you use a return keyword in the method?
Yes, Even though a method's return type is void, you can use the return keyword to stop the execution of the method as shown in the example below.
using System;
namespace Demo
{
class Program
{
public static void Main()
{
SayHi();
}
public static void SayHi()
{
Console.WriteLine("Hi");
return;
Console.WriteLine("This statement will never be executed");
}
}
}
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